The slide presents two solved integral examples in a two-column format. On the left, it computes the indefinite integral ∫(2x + 3) dx as x² + 3x + C using the power rule. On the right, it evaluates the definite integral ∫₀² x² dx as 8/3, representing the area under the curve from 0 to 2.
Solved Examples
| Indefinite Integral Example | Definite Integral Example |
|---|
| Compute ∫(2x + 3) dx.
Apply power rule: ∫2x dx = 2(x²/2) = x² ∫3 dx = 3x Thus, ∫(2x + 3) dx = x² + 3x + C
Basic antiderivative with constant. | Evaluate ∫₀² x² dx.
Antiderivative: x³/3 At upper limit x=2: (2³)/3 = 8/3 At lower limit x=0: 0 Result: [x³/3]₀² = 8/3 - 0 = 8/3
Represents area under x² from 0 to 2. |
Source: Calculus Integration*
Speaker Notes
Demonstrate basic indefinite and definite integration. Left: Fundamental antiderivative rule. Right: Evaluate definite integral with limits. Key for understanding area under curve.